14=2b+b^2

Solution for 14=2b+b^2 equation:

14=2b+b^2

We move all terms to the left:

14-(2b+b^2)=0

We get rid of parentheses

-b^2-2b+14=0

We add all the numbers together, and all the variables

-1b^2-2b+14=0

a = -1; b = -2; c = +14;
Δ = b2-4ac
Δ = -22-4·(-1)·14
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{15}}{2*-1}=\frac{2-2\sqrt{15}}{-2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{15}}{2*-1}=\frac{2+2\sqrt{15}}{-2}
$